10 2017-10-02  Concurs de Casa BC Brasov
Dan Moraru - Sandor Balint
   

Result list  <<  >>  1  2  3  4  5  6  7  8  9  10

Pair: 10    Dan Moraru - Sandor Balint

Score: 110.00    50.93 %    Rank: 7    
                            
Rnd  Tbl   As  Opp  Board  Contr    Ld     Result  Score    %     Round   %       Acc      %        Opponent name

 1    1   N-S   1     1    1N  N  = CA     90       6.00   75                                       Cristea - Goada
                      2    3N  W  = D8       -400   3.00   38                                               
                      3    6H  S -2 SA       -100   0.00    0      9.00  38      9.00  37.50                

 2    1   N-S   2     4    4S  E  = D4       -620   2.00   25                                       Voinescu - Grieger
                      5    1N  N +1 H4    120       4.00   50                                               
                      6    6H  N -2 D7       -100   0.00    0      6.00  25     15.00  31.25                

 3    1   N-S   3     7    4S  N  = D8    620       5.00   63                                       Mihalcica - Spiridonescu
                      8    3N  W +1 SQ       -430   6.00   75                                               
                      9    2N  S  = HK    120       3.00   38     14.00  58     29.00  40.28                

 4    1   N-S   4     10   4H  W +2 CK       -680   2.00   25                                       Orban - Nicolau
                      11   3N  N  = S10   400       4.00   50                                               
                      12   3D  W  = HQ       -110   4.00   50     10.00  42     39.00  40.63                

 5    1   N-S   5     13   3H  N -1 SA       -100   6.00   75                                       Hecht - Leiter
                      14   3C  E -1 H8     50       6.00   75                                               
                      15   3Dx E -1 CA    100       2.00   25     14.00  58     53.00  44.17                

 6    1   N-S   6     16   4C  W -1 HK    100       7.00   88                                       Craciun - Popa
                      17   2H  N  = HK    110       6.00   75                                               
                      18   1N  W -1 HJ     50       7.00   88     20.00  83     73.00  50.69                

 7    1   N-S   7     19   4S  W +2 C2       -680   0.00    0                                       Babos - Toma
                      20   4Hx N -3 CK       -800   0.00    0                                               
                      21   1N  N -1 S9       -100   5.00   63      5.00  21     78.00  46.43                

 8    1   N-S   8     22   3H  S -1 DJ        -50   6.00   75                                       Bura - Damboianu
                      23   4H  N  = S5    620       7.00   88                                               
                      24   4Sx S -1 DK       -100   2.00   25     15.00  63     93.00  48.44                

 9    1   N-S   9     25   3N  W +2 C10      -660   2.00   25                                       Iacob - Grozea
                      26   4Hx N  = DQ    790       8.00  100                                               
                      27   3N  S  = H9    400       7.00   88     17.00  71    110.00  50.93                


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